Exercises: Errors and Debugging Solutions¶

Find and Fix Syntax Errors¶

Error 1: Line 6 Correct syntax should look like this:
```
value = int(input("Enter an index value: "))
```
Error 2: Line 9 Correct syntax should look like this
```
if value > len(alphabet):
```

Error 3: Line 12 Correct syntax should look like this:

print("The letter at index {0} is '{1}'.".format(index, alphabet[index]))

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Find and Fix Runtime Errors¶

Error 1: Line 2: One option for correct syntax could be this:

print("The last letter in '{0}' is '{1}'".format(word, word[-1]))

Error 2: Line 5: What data type is user input? What data type do you need? Correct syntax could be this:
```
second_num = int(input("Enter another whole number: "))
```

Error 3: Line 10: Correct the variable name typo

print("\tProduct = {0}".format(first_num * second_num))

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Solve Logic Errors¶

Part 1: Calculate a Percentage
1. Errors 1 and 2: Line 5: Correct syntax could look like this:
```
percentage = points_earned/points_possible * 100
```
Part 2: Convert a Student’s Percentage into a Letter Grade
1. Error 1: Lines 8, 10, 12, 14, & 16: Fix the Letter Grades
2. Error 2: Lines 7, 9, 11, 13: Change > or < to include the value as well. You could also update the order of percentage ranges, too. One solution could start like this:
```
if score_percent >= 90:
   letter_grade = 'A'
elif score_percent >= 80:
   letter_grade = "B"

# rest of code...
```

Part 3: Validating a Username:

Testing with print() statements: This is a demo, but syntax could look like this:

if len(username) >= 5 and len(username) <= 10:
   is_valid = True

print(is_valid)  #testing with print is a easy way to check your work

Error 1: Lines 13-18: Correct syntax could look like this.

for char in username:
   if char in string.digits:
      has_digit = True
   elif char not in string.ascii_letters:
      is_valid = False
   # else:                 #else statement not needed
      # is_valid = True

print(is_valid)

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