5.5. Nested Conditionals¶
We can write code with more complex branching behavior by combining conditionals and, in particular, by nesting conditionals. Let's see how this works by tackling the following problem.
Example
Write code that prints different messages based on the value of a number variable. If the number is odd, print nothing. If it is even, print "EVEN". If it is also positive print "POSITIVE".
Our first attempt at a solution might look like this:
1 2 3 4 5 6 7 8 9 | let num = 7;
if (num % 2 === 0) {
console.log("EVEN");
}
if (num > 0) {
console.log("POSITIVE");
}
|
Console Output
POSITIVE
We find that the output is POSITIVE
, even though 7 is odd and so nothing
should be printed. This code doesn't work as desired because we only want to
test for positivity when we already know that the number is even. We can
enable this behavior by putting the second conditional inside the first.
1 2 3 4 5 6 7 8 9 | let num = 7;
if (num % 2 === 0) {
console.log("EVEN");
if (num > 0) {
console.log("POSITIVE");
}
}
|
Try It!
Run the previous example with several different values for num
(even,
odd, positive, negative) to ensure it works as desired. Nice, huh?
Notice that when we put one conditional inside another, the body of the nested conditional is indented by two tabs rather than one. This convention provides an easy, visual way to determine which code is part of which conditional.
5.5.1. Check Your Understanding¶
Question
What is printed when the following code runs?
1 2 3 4 5 6 7 | let num = 7;
if (num % 2 === 0) {
if (num % 2 === 1) {
console.log("odd");
}
}
|
The code won't run due to invalid syntax
odd
even
The code runs but doesn't print anything
Question
Considering the same conditional used in the previous question, which values of num
would result in "odd"
being printed?
1 2 3 4 5 | if (num % 2 === 0) {
if (num % 2 === 1) {
console.log("odd");
}
}
|
Even values of
num
.Odd values of
num
.No values. It is impossible for the call to
console.log
to ever run, given the two conditions.num
is 0.